document.write( "Question 1110899: Lucas is 9 years older than three times his son's age. In 5 years, the age of Lucas will be 6 years more than twice his son's age. Find their present age. \n" ); document.write( "

Algebra.Com's Answer #725918 by ikleyn(52790) $\"\"$ $\"About$

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document.write( "L = 9 + 3*S,             (1)\r\n" );
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document.write( "L + 5 = 6 + 2*(S+5).     (2)\r\n" );
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document.write( "Substitute (1) into (2).  You will get\r\n" );
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document.write( "9 + 3*S + 5 = 6 + 2S + 10,\r\n" );
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document.write( "S = 6 + 10 - 9 - 5 = 2.\r\n" );
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document.write( "Thus we found that the son is 2 years old.\r\n" );
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document.write( "Then Lucas (= the father of his son) is 9 + 3*2 = 9 + 6 = 15 years old.\r\n" );
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