document.write( "Question 1110895: Log_64(4^4)=x+1 \n" ); document.write( "
Algebra.Com's Answer #725917 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
\"log%2864%2C4%5E4%29=x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"4%2Alog%2864%2C4%29=x%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=4%2Alog%2864%2C4%29-1\"\r
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\n" ); document.write( "\n" ); document.write( "CHANGE OF BASE FORMULA - CHOOSING BASE 2\r
\n" ); document.write( "\n" ); document.write( "\"x=4%28log%282%2C4%29%2Flog%282%2C64%29%29-1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=4%28log%282%2C2%5E2%29%2Flog%282%2C2%5E4%29%29-1\"-------step is mistake. exponent 4 should be exponent 6.\r
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\n" ); document.write( "\n" ); document.write( "The rest of this is wrong:
\n" ); document.write( "\"x=2-1\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=1%29\"
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