document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110902>Question 1110902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains leave towns 1220km apart at the same time and travel toward each other. One train travels 10km/h slower than the other. If they meet in 5 hours, what is the rate of each train? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725904 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two trains leave towns 1220km apart at the same time and travel toward each other. One train travels 10km/h slower than the other. If they meet in 5 hours, what is the rate of each train?\r<BR>\n" );
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document.write( "Let speed of one train be x<BR>\n" );
document.write( "other train speed = (x+10)\r<BR>\n" );
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document.write( "they are moving towards each other<BR>\n" );
document.write( "Effective speed = x+x+10 -> 2x+10\r<BR>\n" );
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document.write( "d= speed 8 time<BR>\n" );
document.write( "1220 = (2x+10) *5<BR>\n" );
document.write( "244 = 2x+10\r<BR>\n" );
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document.write( "244 = 2x\r<BR>\n" );
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document.write( "x= 122 km/h speed of first train\r<BR>\n" );
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document.write( "add 10 to get speed of other train<BR>\n" );
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