document.write( "Question 99718: Find two consective odd intergers whose sum is 116. \n" ); document.write( "
Algebra.Com's Answer #72589 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Consecutive odd integers follow the form: \"2x%2B1\", \"2x%2B3\", \"2x%2B5\", ...., etc\r
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\n" ); document.write( "\n" ); document.write( "So the sum of two consecutive odd integers is:\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%2B1%29%2B%282x%2B3%29=116\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B1%2B2x%2B3=116\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"4x%2B4=116\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"4x=116-4\"Subtract 4 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"4x=112\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28112%29%2F%284%29\" Divide both sides by 4 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=28\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=28\" \r
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\n" ); document.write( "\n" ); document.write( "Since \"x=28\", our first number is \r
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\n" ); document.write( "\n" ); document.write( "\"2%2828%29%2B1=57\"\r
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\n" ); document.write( "\n" ); document.write( "So our first number is 57\r
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\n" ); document.write( "\n" ); document.write( "and our second number is \r
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\n" ); document.write( "\n" ); document.write( "\"2%2828%29%2B3=59\"\r
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\n" ); document.write( "\n" ); document.write( "So our second number is 59\r
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\n" ); document.write( "\n" ); document.write( "So our two numbers are 57 and 59\r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "\"57%2B59=116\"\r
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\n" ); document.write( "\n" ); document.write( "\"116=116\" works
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