document.write( "Question 1110879: megan traveled 165 miles to visit friends. on the return trip she was delayed by construction and had to reduce her average speed by 22 miles per hour. the return trip took 2 hours longer. what was the time and average speed for each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #725875 by josgarithmetic(39617)\"\" \"About 
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document.write( "                 SPEED        TIME          DISTANCE\r\n" );
document.write( "GOING            r            165/r          165\r\n" );
document.write( "RETURN           r-22         165/(r-22)     165\r\n" );
document.write( "DIFFERENCE                      2\r\n" );
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\n" ); document.write( "\n" ); document.write( "The main unknown quantity is the speed GOING TO the destination, r.\r
\n" ); document.write( "\n" ); document.write( "\"165%2F%28r-22%29-165%2Fr=2\"
\n" ); document.write( "Solve this for r, and evaluate the other rate and both times.
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