document.write( "Question 99676: Given F(X) = 4X^2 - 12X, solve f(X) > 0. \n" ); document.write( "
Algebra.Com's Answer #72583 by edjones(8007)\"\" \"About 
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4x^2-12x>0
\n" ); document.write( "factor: 4x(x-3)>0
\n" ); document.write( "4x>0...x>0
\n" ); document.write( "x>3
\n" ); document.write( "Test point method find a value of f(x) below 0, between 0 and 3, and above 3:
\n" ); document.write( "f(-1)=16
\n" ); document.write( "f(1)=-8
\n" ); document.write( "f(4)=16
\n" ); document.write( "f(x)>0 when x<0 or x>3
\n" ); document.write( "the graph tells all.
\n" ); document.write( "Ed
\n" ); document.write( "\"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C4x%5E2-12x%29\"
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