document.write( "Question 99701: a number plus two third of itself plus one half of itself plus one seventh of itself equal 97. find the no. \n" ); document.write( "

Algebra.Com's Answer #72582 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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a number plus two third of itself
\n" ); document.write( " 1 $\"2%2F3\"$ x = $\"5%2F3\"$ x
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\n" ); document.write( " plus one half of itself
\n" ); document.write( " + $\"1%2F2\"$ x
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\n" ); document.write( " plus one seventh of itself
\n" ); document.write( " + $\"1%2F7\"$ x
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\n" ); document.write( " equal 97.
\n" ); document.write( " $\"5%2F3\"$ x + $\"1%2F2\"$ x + $\"1%2F7\"$ x = 97
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\n" ); document.write( "find the no.
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\n" ); document.write( "A multiple of all 3 denominators is 42:
\n" ); document.write( "42* $\"5%2F3\"$ x + 42* $\"1%2F2\"$ x + 42* $\"1%2F7\"$ x = 42(97)
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\n" ); document.write( "CAncel out the denominators:
\n" ); document.write( "14(5x) + 21x + 6x = 4074
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\n" ); document.write( "70x + 21x + 6x = 4074
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\n" ); document.write( "97x = 4074
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\n" ); document.write( "x = 4074/97
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\n" ); document.write( "x = 42
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\n" ); document.write( "Check solution in original equation:
\n" ); document.write( " $\"5%2F3\"$ *42 + $\"1%2F2\"$ *42 + $\"1%2F7\"$ *42 = 97
\n" ); document.write( " 70 + 21 + 6 = 97
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\n" ); document.write( "Pretty simple, right? \n" ); document.write( "

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