document.write( "Question 1110812: father is twice as old as his son. three years ago, he was 19 less than thrice the age of his son. how old is the father now? \n" ); document.write( "
Algebra.Com's Answer #725817 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! father is twice as old as his son. \n" ); document.write( "f = 2s \n" ); document.write( " three years ago, he was 19 less than thrice the age of his son. \n" ); document.write( "f - 3 = 3(s-3) - 19 \n" ); document.write( "f - 3 = 3s - 9 \n" ); document.write( "f = 3s - 9 - 19 + 3 \n" ); document.write( "f = 3s - 25 \n" ); document.write( "replace f with 2s \n" ); document.write( "2s = 3s - 25 \n" ); document.write( "25 = 3s - 2s \n" ); document.write( "s = 25 yrs is the son's age \n" ); document.write( "ad \n" ); document.write( "2(25) = 50 yrs is the father's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out in the statement \n" ); document.write( "\"three years ago, he was 19 less than thrice the age of his son.\" \n" ); document.write( "50 - 3 = 3(25-3) - 19 \n" ); document.write( "47 = 3(22) - 19 \n" ); document.write( "47 = 66 - 19 \n" ); document.write( " |