document.write( "Question 1110812: father is twice as old as his son. three years ago, he was 19 less than thrice the age of his son. how old is the father now? \n" ); document.write( "
Algebra.Com's Answer #725817 by ankor@dixie-net.com(22740)\"\" \"About 
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father is twice as old as his son.
\n" ); document.write( "f = 2s
\n" ); document.write( " three years ago, he was 19 less than thrice the age of his son.
\n" ); document.write( "f - 3 = 3(s-3) - 19
\n" ); document.write( "f - 3 = 3s - 9
\n" ); document.write( "f = 3s - 9 - 19 + 3
\n" ); document.write( "f = 3s - 25
\n" ); document.write( "replace f with 2s
\n" ); document.write( "2s = 3s - 25
\n" ); document.write( "25 = 3s - 2s
\n" ); document.write( "s = 25 yrs is the son's age
\n" ); document.write( "ad
\n" ); document.write( "2(25) = 50 yrs is the father's age
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\n" ); document.write( "See if that checks out in the statement
\n" ); document.write( "\"three years ago, he was 19 less than thrice the age of his son.\"
\n" ); document.write( "50 - 3 = 3(25-3) - 19
\n" ); document.write( "47 = 3(22) - 19
\n" ); document.write( "47 = 66 - 19
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