document.write( "Question 1110761: Problem Page Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $45 . For one performance, 40 advance tickets and 20 same-day tickets were sold. The total amount paid for the tickets was $1300 . What was the price of each kind of ticket? \n" ); document.write( "

Algebra.Com's Answer #725788 by ikleyn(52778) $\"\"$ $\"About$

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document.write( "Combine the tickets in groups in this way:\r\n" );
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document.write( " 40 advance tickets + 20 same day tickets = \r\n" );
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document.write( "(20 advance tickets + 20 same say tickets) + 20 advance tickets.\r\n" );
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document.write( "Now the total cost is\r\n" );
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document.write( "1300 = 20*45 + 20a,  where \"a\" is the cost of the advance ticket.\r\n" );
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document.write( "It gives  20a = 1300-900 = 400.\r\n" );
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document.write( "Hence,  a =  = 20 dollars is the price of one advance ticket.\r\n" );
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document.write( "Then the price of one same day ticket is  45-20 = 25 dollars.\r\n" );
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\n" ); document.write( "\n" ); document.write( " The lesson to learn from this solution: You do not need to solve the system of equations to get the answer.\r
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