document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110757>Question 1110757</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The side of one square is equal to 1m, and its diagonal is equal to the side of a second square. Find the diagonal of the second square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725770 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diagonal of the first square is  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt%281%5E2%2B1%5E2%29+=+sqrt%282%29+ ALIGN=MIDDLE  ALT=\"+sqrt%281%5E2%2B1%5E2%29+=+sqrt%282%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "The diagonal of the 2nd square is then  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt%28%28sqrt%282%29%29%5E2+%2B+%28sqrt%282%29%29%5E2%29+=+sqrt%282%2B2%29+=+sqrt%284%29+=+highlight%282m%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );