document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110738>Question 1110738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Problem Page Two buses leave a station at the same time and travel in opposite directions. One bus travels 16 /kmh faster than the other. If the two buses are 1270km apart after 5 hours, what is the rate of each bus </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725764 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let speed of one bus be x kmh<BR>\n" );
document.write( "the other will be (x+16)   kmh\r<BR>\n" );
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document.write( "they are moving in opposite directions<BR>\n" );
document.write( "so effective speed  is x+x+16 -> 2x+16\r<BR>\n" );
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document.write( "distance = 1270 km<BR>\n" );
document.write( "time = 5 hours\r<BR>\n" );
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document.write( "d= s x t<BR>\n" );
document.write( "1270 = (2x+16) *5<BR>\n" );
document.write( "1270/5 = 2x +16<BR>\n" );
document.write( "254 = 2x+16<BR>\n" );
document.write( "2x= 238<BR>\n" );
document.write( "x= 119 km/h<BR>\n" );
document.write( "add 16 to get speed of second bus </SPAN>\n" );
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