document.write( "Question 1110326: A researcher wishes to estimate, with
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document.write( "9999%
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document.write( "confidence, the population proportion of adults who think the president of their country can control the price of gasoline. Her estimate must be accurate within
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document.write( "44%
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document.write( "of the true proportion.
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document.write( "a) No preliminary estimate is available. Find the minimum sample size needed.\r
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document.write( "b) Find the minimum sample size needed, using a prior study that found that
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document.write( "1818%
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document.write( "of the respondents said they think their president can control the price of gasoline.
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document.write( "c) Compare the results from parts (a) and (b). \n" );
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Algebra.Com's Answer #725727 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Within 4% and confidence 99% \n" ); document.write( "the error 0.04=z* sqrt (SE), where z=2.576 and SE is sqrt (p*(1-p))/n. Use 0.5 when no estimate is available, since that is the most conservative (largest) product of two decimals whose sum is 1. \n" ); document.write( "2.576*sqrt(0.25)/sqrt (n) equals error \n" ); document.write( "2.576*0.5/sqrt (n)=0.04 \n" ); document.write( "1.288/0.04=sqrt(n); square both sides \n" ); document.write( "n=1036.84 or 1037.\r \n" ); document.write( "\n" ); document.write( "With a known fraction of 0.18, p*(1-p)=0.1476 \n" ); document.write( "(1.288/0.1476)^2=76.15 or 77 \n" ); document.write( "When a prior estimate is available and is significantly different from 0.5, the sample size falls dramatically.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |