document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110704>Question 1110704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bella Sandino made a $600 loan to her friend, Sadie, at 11%. Sadie paid back the loan with interest of $19.25. How long in days was the loan outstanding? (Use 360 days a year.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725726 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> She paid back $619.25<BR>\n" );
document.write( "619.25=600(1+r/n)=600(1+.11n/360); when n=360, the parentheses will equal 1.11<BR>\n" );
document.write( "619.25/600=1+.11n/360<BR>\n" );
document.write( "1.03208=1+.11/n<BR>\n" );
document.write( ".03208=.11n/360<BR>\n" );
document.write( ".11n=360*.03208=11.5488<BR>\n" );
document.write( "n=104.99 days or 105 days  ANSWER<BR>\n" );
document.write( "This is between a 1/4 and 1/3 of a year, and 1 years' interest is $66, so the answer should be between $16.50 and $22.<BR>\n" );
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