document.write( "Question 1110637: A rocket accelerates from rest at the rate of 55 m/s^2 for 20 s. It then moves at a constant speed for 5 s after which it accelerates at -35 m/s^2 until it stops. What is the distance travelled during the slowing down period? \n" ); document.write( "
Algebra.Com's Answer #725644 by KMST(5328)\"\" \"About 
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Accelerating from rest at the rate of \"55\"\"m\"\"%22%2F%22\"\"s%5E2\" for \"20+s\" ,
\n" ); document.write( "the rocket would attain a speed of \"55%2A20\"\"%22m+%2F+s%22=%221100+m+%2F+s%22\" .
\n" ); document.write( "When it later decelerates with a constant \"-35\"\"m\"\"%22%2F%22\"\"s%5E2\" acceleration,
\n" ); document.write( "it takes \"1100%2F35\"\"s\" until it stops
\n" ); document.write( "During that slow down period the rocket's speed decreases linearly,
\n" ); document.write( "with an average speed of \"1100%2F2\"\"%22m+%2F+s%22\" .
\n" ); document.write( "During that period, travelling at that average velocity, it travels
\n" ); document.write( "\"%281100%2F2%29%281100%2F35%29\"\"m=1100%5E2%2F70\"\"m=highlight%28518571m%29\" (rounded to the nearest meter).
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\n" ); document.write( "NOTE: I can write formulas, so if you want them ask,
\n" ); document.write( "but I saw no need to complicate a simple way to the solution.
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