document.write( "Question 1110629: $2500 is invested at 6% per year compounded annually. How long will it take this investment to grow to $10,000? \n" ); document.write( "
Algebra.Com's Answer #725630 by addingup(3677)![]() ![]() You can put this solution on YOUR website! 2500(1+0.06)^t = 10000 \n" ); document.write( "1.06^t = 4 \n" ); document.write( "tlog(1.06) = log(4) \n" ); document.write( "t = log(4)/log(1.06) \n" ); document.write( "t = 23.8 years \n" ); document.write( "------------------------------------ \n" ); document.write( "Check: \n" ); document.write( "2500(1+.06)^23.8 = 2500(1.06)^23.8 = 2500*4 = 10000 Correct \n" ); document.write( " \n" ); document.write( " |