document.write( "Question 99686: meera mother is four times as old as meera. after 5 years her mother will be three times as old as she will be then what are their present age. \n" ); document.write( "

Algebra.Com's Answer #72563 by Adam(64) $\"\"$ $\"About$

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We denote mother's age by x. And Meera's age by y. We can write 4*y = x or x/4=y the second equation might be (x+5)/3=y+5 or 3*(y+5)=x+5. Let's choose second option and create a system of 2 linear equations with 2 variables.\r
\n" ); document.write( "\n" ); document.write( "4*y = x
\n" ); document.write( "3*(y+5)=x+5
\n" ); document.write( "We can substitute x in terms of y into second equation, so we get the equation with only variable.
\n" ); document.write( "3*(y+5)=4*y+5 multiply
\n" ); document.write( "3*y+15=4*y+5 subtract 3*y
\n" ); document.write( "15=4*y-3*y+5
\n" ); document.write( "15=y+5 /-5
\n" ); document.write( "10=y
\n" ); document.write( "Now we know that Meera is presently 10 years old.
\n" ); document.write( "We can substitute our result into any equation of the original system.
\n" ); document.write( "4*10 = x
\n" ); document.write( "40= x
\n" ); document.write( "Mother's present age is 40.\r
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