document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110633>Question 1110633</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 64cm. The length is 4cm less than twice the width. Find the length and the width .\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725627 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L + 2W = 64<BR>\n" );
document.write( "L = 2W - 4 substitute above for L:<BR>\n" );
document.write( "2(2W - 4) + 2W = 64<BR>\n" );
document.write( "4W - 8 + 2W = 64<BR>\n" );
document.write( "6W = 72<BR>\n" );
document.write( "W = 12<BR>\n" );
document.write( "and L?<BR>\n" );
document.write( "L = 2W - 4 = 2(12) - 4 = 24 - 4 = 20<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "2L + 2W = 64<BR>\n" );
document.write( "2(20) + 2(12) = 64<BR>\n" );
document.write( "40 + 24 = 64 Correct<BR>\n" );
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