document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110389>Question 1110389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bushwalker walks 8 km on a bearing of 116 degrees from L to M, then proceeds to walk a further 13km to N on a bearing of 026 degrees.<BR>\n" );
document.write( "a) calculate his distance from L, correct to the nearest km.<BR>\n" );
document.write( "b) find his bearing from L, correct to the nearest degree </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725592 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If this is drawn out, it is a right triangle with LMN being a right angle. <BR>\n" );
document.write( "One leg is 8, the other 13 and the hypotenuse is sqrt (233) or 15.26 km distance.<BR>\n" );
document.write( "The bearing is tangent of L, which is two parts, known 26 degrees south of east plus another component north of east.  That combined tangent is 13/8, opposite over adjacent, or 1.625.  The arc tan (1.625) is 58.39 deg, making the missing angle 32.39 north of east or true bearing of 57.61 deg. </SPAN>\n" );
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