document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110610>Question 1110610</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Mark road his new Harley 60 mph for part of the trip and 70 miles per hour for the rest of the trip home from the Shakespeare Festival in Ashland,Oregon. If the entire trip was 250 miles, and he spent twice as much time traveling at the faster speed, how many miles was he able to travel at each rate.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725591 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Mark road his new Harley 60 mph for part of the trip and 70 miles per hour for the rest of the trip home from the Shakespeare Festival in Ashland,Oregon. If the entire trip was 250 miles, and he spent twice as much time traveling at the faster speed, how many miles was he able to travel at each rate. <BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "slower rate DATA::<BR>\n" );
document.write( "rate = 60 mph ; distance = d miles ; time = d/60 hrs<BR>\n" );
document.write( "----<BR>\n" );
document.write( "faster rate DATA:<BR>\n" );
document.write( "rate = 70 mph ; distance = 250-d ; time = (250-d)/70 hrs<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "Equation::<BR>\n" );
document.write( "faster time = 2(slower time)<BR>\n" );
document.write( "(250-d)/70 = 2(d/60)<BR>\n" );
document.write( "------<BR>\n" );
document.write( "(250/60d) - (d^2/60) = (140/60)d<BR>\n" );
document.write( "---------------------------------<BR>\n" );
document.write( "d^2/60 - (110/60)d = 0<BR>\n" );
document.write( "d^2 - 110d = 0<BR>\n" );
document.write( "d(d-110) = 0<BR>\n" );
document.write( "Positive solution::<BR>\n" );
document.write( "distance = 110 miles (distance at slower rate)<BR>\n" );
document.write( "250-d = 140 miles (distance at faster rate)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----------<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );