document.write( "Question 1110608: Sally is traveling 50 mph and Mark is traveling 65 mph. How long will it take Mark to catch up if Sally had a two hour headstart? \n" ); document.write( "
Algebra.Com's Answer #725590 by ikleyn(52788)\"\" \"About 
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document.write( "How long will it take Mark to catch up Sally = \"%282%2A50%29%2F%2865-50%29\" = \"100%2F15\" = \"20%2F3\" = \"6\"\"2%2F3\" hours = 6 hours and 40 minutes.\r\n" );
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document.write( "Explanation.  The numerator 2*50 = 100 miles is the Sally's head start distance.\r\n" );
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document.write( "              The denominator (65-50) = 15 mph is their relative speed, i.e. the rate of decreasing the initial 100 km distance between them.\r\n" );
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\n" ); document.write( "See introductory lessons on Travel and Distance problems\r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in opposite directions \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in the same direction (catching up)\r
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\n" ); document.write( "\n" ); document.write( "You will find the solutions of many similar problems there.\r
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\n" ); document.write( "\n" ); document.write( "Read them and learn once for all from these lessons on how to solve simple Travel and Distance problems.\r
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