document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110584>Question 1110584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bag contain two white and three black balls. Obtain a probability distribution of the number of white balls if two balls are selected </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725570 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725570\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(0 white) = (3/5)(2/4) = 6/20 =  <b> 3/10 </b><BR>\n" );
document.write( "P(1 white) =  P(white then black) + P(black then white) <BR>\n" );
document.write( "                 =  (2/5)(3/4) + (3/5)(2/4) = 6/20 + 6/20 = 12/20 = <b> 6/10 </b><BR>\n" );
document.write( "P(2 white) = (2/5)(1/4) = 2/20 = <b> 1/10 </b>\r<BR>\n" );
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document.write( "—<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "Since one of the above events MUST happen, the sum of their probabilities must be 1:<BR>\n" );
document.write( "3/10 + 6/10 + 1/10 = 10/10 = 1   (ok)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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