document.write( "Question 1110419: The length of the shorter side of a parallelogram is 29 cm. A perpendicular line segment, which goes through the point of intersection of the diagonals to the longer side divides this longer side into two segments: 33 cm and 12 cm. What is the area of the parallelogram? \n" ); document.write( "

Algebra.Com's Answer #725404 by ikleyn(52784) $\"\"$ $\"About$

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document.write( "The area of a parallelogram  is the product of its base measure by its height measure.\r\n" );
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document.write( "The base has the measure of  33+12 = 45 cm.\r\n" );
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document.write( "All you need to find is the measure of the height drawn to the base.\r\n" );
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document.write( "Let ABCD be your parallelogram with the longer side AB of 29+12 = 45 cm long.\r\n" );
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document.write( "Draw the height (the perpendicular) to the side AB from the vertex C.\r\n" );
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document.write( "You will get a right angled triangle with the hypotenuse of 29 cm and one leg of 33-12 = 21 cm.  Hence, its other leg is  = 20 cm.\r\n" );
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document.write( "This other leg is the height of the parallelogram.\r\n" );
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document.write( "Now the area of the parallelogram is  45*20 = 900 cm^2.\r\n" );
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