document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110391>Question 1110391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given ABCD is a parallelogram with vertices A (-1, -4), B (1,2) and C (3, 3), find the equation of the line BD </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725385 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "First find the gradient of BC<BR>\n" );
document.write( "y2 - y1/x2 - x1 = 3 - 2/3 - 1 = 1/2<BR>\n" );
document.write( "Now AD will have the same gradient (parallelogram's sides)<BR>\n" );
document.write( "Coordinates for point D (x, y)<BR>\n" );
document.write( "Gradient of AD y - (-4)/x - (-1) = y + 4/x + 1<BR>\n" );
document.write( "y + 4/x + 1 = 1/2: y = -3 x = 1<BR>\n" );
document.write( "D(1, -3)<BR>\n" );
document.write( "As D and B have the same x coordinate<BR>\n" );
document.write( "Equation of line BD => x = 1<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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