document.write( "Question 1110410: Charles invested income in two accounts, one paying 3% annual simple interest and the other paying 2% interest. He earned a total of $11 interest. If he invested three times as much in the 3% account as he did in the 2% account, how much did he invest at each rate ? \n" ); document.write( "
Algebra.Com's Answer #725382 by josmiceli(19441)\"\" \"About 
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For the 3% rate:
\n" ); document.write( "(1) \"+I+=+3P%2A.03%2A1+\"
\n" ); document.write( "For the 2% rate:
\n" ); document.write( "(2) \"+11+-+I+=+P%2A.02%2A1+\"
\n" ); document.write( "------------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+11+-+.03%2A3P+=+.02P+\"
\n" ); document.write( "(2) \"+11+-+.09P+=+.02P+\"
\n" ); document.write( "(2) \"+.11P+=+11+\"
\n" ); document.write( "(2) \"+P+=+100+\"
\n" ); document.write( "and
\n" ); document.write( "\"+3P+=+300+\"
\n" ); document.write( "---------------------
\n" ); document.write( "He invested $300 @ 3% and $100 @ 2%
\n" ); document.write( "-------------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+I+=+.09P+\"
\n" ); document.write( "(1) \"+I+=+.09%2A100+\"
\n" ); document.write( "(1) \"+I+=+9+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+11+-+I+=+.02P+\"
\n" ); document.write( "(2) \"+11+-+I+=+.02%2A100+\"
\n" ); document.write( "(2) \"+I+=+11+-+2+\"
\n" ); document.write( "(2) \"+I+=+9+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
\n" );