document.write( "Question 1110368: ABCD is a trapezoid. E is a point between B and C. 2|BE| = |EC|, 5|AB| = 3|DC|
\n" ); document.write( "Area of DEC is 10. So what is area of AED?
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Algebra.Com's Answer #725366 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The answer is 11\r
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\n" ); document.write( "\n" ); document.write( "See the steps below to see how I got that answer\r
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\n" ); document.write( "\n" ); document.write( "A diagram isn't 100% mandatory, but for me it really helps.
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\n" ); document.write( "Based on the diagram we have...
\n" ); document.write( "x = vertical distance from point C to point E
\n" ); document.write( "y = vertical distance from point E to point B
\n" ); document.write( "z = |AB| = distance from A to B
\n" ); document.write( "w = |DC| = distance from C to D
\n" ); document.write( "T1 = area of the gray triangle ABE
\n" ); document.write( "T2 = area of the green triangle AED
\n" ); document.write( "T3 = area of the red triangle DEC\r
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\n" ); document.write( "\n" ); document.write( "Because 2|BE| = |EC| and because E is on segment BC, this means that the vertical component from C to E is twice that as the vertical component from E to B.
\n" ); document.write( "In other words, x = 2y\r
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\n" ); document.write( "\n" ); document.write( "Also,
\n" ); document.write( "5|AB| = 3|DC|
\n" ); document.write( "5*z = 3*w
\n" ); document.write( "w = 5z/3\r
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\n" ); document.write( "\n" ); document.write( "We will use the two equations x = 2y and w = 5z/3 for the sections below
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\n" ); document.write( "T3 = area of triangle DEC (red triangle)
\n" ); document.write( "T3 = (base*height)/2
\n" ); document.write( "T3 = x*w/2
\n" ); document.write( "10 = x*w/2 .... plug in the given area for triangle DEC (which was 10 square units)
\n" ); document.write( "2*10 = x*w
\n" ); document.write( "20 = x*w
\n" ); document.write( "20 = (2y)*(5z/3) .... plug in x = 2y; plug in w = 5z/3
\n" ); document.write( "20 = 10yz/3
\n" ); document.write( "3*20 = 10yz
\n" ); document.write( "60 = 10yz
\n" ); document.write( "6 = yz
\n" ); document.write( "yz = 6 ... this will be used later
\n" ); document.write( "--------
\n" ); document.write( "A = area of trapezoid
\n" ); document.write( "A = height*(base1+base2)/2
\n" ); document.write( "A = h*(b1+b2)/2
\n" ); document.write( "A = (x+y)*(w+z)/2
\n" ); document.write( "A = (2y+y)*(w+z)/2 .... plug in x = 2y
\n" ); document.write( "A = 3y*(w+z)/2
\n" ); document.write( "A = 3y*(5z/3+z)/2 .... plug in w = 5z/3
\n" ); document.write( "A = 3y*(5z/3+3z/3)/2
\n" ); document.write( "A = 3y*(8z/3)/2
\n" ); document.write( "A = 3y*8z/6
\n" ); document.write( "A = 3y*4z/3
\n" ); document.write( "A = 12yz/3
\n" ); document.write( "A = 4yz
\n" ); document.write( "A = 4*6 .... replace yz with 6 (since it was found earlier that yz = 6)
\n" ); document.write( "A = 24
\n" ); document.write( "The area of the trapezoid is 24 square units
\n" ); document.write( "--------
\n" ); document.write( "T1 = area of gray triangle ABE
\n" ); document.write( "T1 = (base*height)/2
\n" ); document.write( "T1 = z*y/2
\n" ); document.write( "T1 = yz/2
\n" ); document.write( "T1 = 6/2 .... replace yz with 6
\n" ); document.write( "T1 = 3
\n" ); document.write( "The gray triangle T1 has area 3 square units
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\n" ); document.write( "T2 = area of green triangle AED (what we want)
\n" ); document.write( "T2 = A - T1 - T3
\n" ); document.write( "T2 = 24 - 3 - 10
\n" ); document.write( "T2 = 11\r
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\n" ); document.write( "\n" ); document.write( "So that's why the answer is 11
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