document.write( "Question 1110368: ABCD is a trapezoid. E is a point between B and C. 2|BE| = |EC|, 5|AB| = 3|DC|
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document.write( "Area of DEC is 10. So what is area of AED? \n" );
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Algebra.Com's Answer #725366 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! The answer is 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "See the steps below to see how I got that answer\r \n" ); document.write( "\n" ); document.write( "----------------------------------------------------------------- \n" ); document.write( "-----------------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "A diagram isn't 100% mandatory, but for me it really helps. \n" ); document.write( " ![]() \n" ); document.write( "Based on the diagram we have... \n" ); document.write( "x = vertical distance from point C to point E \n" ); document.write( "y = vertical distance from point E to point B \n" ); document.write( "z = |AB| = distance from A to B \n" ); document.write( "w = |DC| = distance from C to D \n" ); document.write( "T1 = area of the gray triangle ABE \n" ); document.write( "T2 = area of the green triangle AED \n" ); document.write( "T3 = area of the red triangle DEC\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because 2|BE| = |EC| and because E is on segment BC, this means that the vertical component from C to E is twice that as the vertical component from E to B. \n" ); document.write( "In other words, x = 2y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, \n" ); document.write( "5|AB| = 3|DC| \n" ); document.write( "5*z = 3*w \n" ); document.write( "w = 5z/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We will use the two equations x = 2y and w = 5z/3 for the sections below \n" ); document.write( "-------- \n" ); document.write( "T3 = area of triangle DEC (red triangle) \n" ); document.write( "T3 = (base*height)/2 \n" ); document.write( "T3 = x*w/2 \n" ); document.write( "10 = x*w/2 .... plug in the given area for triangle DEC (which was 10 square units) \n" ); document.write( "2*10 = x*w \n" ); document.write( "20 = x*w \n" ); document.write( "20 = (2y)*(5z/3) .... plug in x = 2y; plug in w = 5z/3 \n" ); document.write( "20 = 10yz/3 \n" ); document.write( "3*20 = 10yz \n" ); document.write( "60 = 10yz \n" ); document.write( "6 = yz \n" ); document.write( "yz = 6 ... this will be used later \n" ); document.write( "-------- \n" ); document.write( "A = area of trapezoid \n" ); document.write( "A = height*(base1+base2)/2 \n" ); document.write( "A = h*(b1+b2)/2 \n" ); document.write( "A = (x+y)*(w+z)/2 \n" ); document.write( "A = (2y+y)*(w+z)/2 .... plug in x = 2y \n" ); document.write( "A = 3y*(w+z)/2 \n" ); document.write( "A = 3y*(5z/3+z)/2 .... plug in w = 5z/3 \n" ); document.write( "A = 3y*(5z/3+3z/3)/2 \n" ); document.write( "A = 3y*(8z/3)/2 \n" ); document.write( "A = 3y*8z/6 \n" ); document.write( "A = 3y*4z/3 \n" ); document.write( "A = 12yz/3 \n" ); document.write( "A = 4yz \n" ); document.write( "A = 4*6 .... replace yz with 6 (since it was found earlier that yz = 6) \n" ); document.write( "A = 24 \n" ); document.write( "The area of the trapezoid is 24 square units \n" ); document.write( "-------- \n" ); document.write( "T1 = area of gray triangle ABE \n" ); document.write( "T1 = (base*height)/2 \n" ); document.write( "T1 = z*y/2 \n" ); document.write( "T1 = yz/2 \n" ); document.write( "T1 = 6/2 .... replace yz with 6 \n" ); document.write( "T1 = 3 \n" ); document.write( "The gray triangle T1 has area 3 square units \n" ); document.write( "-------- \n" ); document.write( "T2 = area of green triangle AED (what we want) \n" ); document.write( "T2 = A - T1 - T3 \n" ); document.write( "T2 = 24 - 3 - 10 \n" ); document.write( "T2 = 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So that's why the answer is 11 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |