document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99666>Question 99666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve.	3x – 7 = 2x + 8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72536 by </B><A HREF=/tutors/aboutme.mpl?userid=doukungfoo><B>doukungfoo(195)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=doukungfoo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=doukungfoo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72536\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x – 7 = 2x + 8<BR>\n" );
document.write( "First move all terms with x to one side of the equal sign<BR>\n" );
document.write( "and all terms without x to the opposited side.<BR>\n" );
document.write( "3x – 2x = 8 + 7<BR>\n" );
document.write( "next combine like terms<BR>\n" );
document.write( "x=15<BR>\n" );
document.write( "Now to check replace x in the original equation with 15<BR>\n" );
document.write( "3x – 7 = 2x + 8<BR>\n" );
document.write( "3(15) – 7 = 2(15) + 8<BR>\n" );
document.write( "45 – 7 = 30 + 8<BR>\n" );
document.write( "38=38 </SPAN>\n" );
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