document.write( "Question 1110369: Find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 40°. \n" ); document.write( "
Algebra.Com's Answer #725354 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 40°.
\n" ); document.write( "-------
\n" ); document.write( "Angle:: x
\n" ); document.write( "supplement:: 180-x
\n" ); document.write( "complement:: 90-x
\n" ); document.write( "---
\n" ); document.write( "Equation::
\n" ); document.write( "180-x -3(90-x) = 40
\n" ); document.write( "180-x -270+3x = 40
\n" ); document.write( "2x -90 = 40
\n" ); document.write( "2x = 130
\n" ); document.write( "x = 65 degrees
\n" ); document.write( "------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "-------- \n" ); document.write( "
\n" );