document.write( "Question 99580: If you add 100 to the number you get a perfect square.
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document.write( "If you add 168 to that number you get another perfect square.
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document.write( "What is that number? \n" );
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Algebra.Com's Answer #72532 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! n=number ... n+100=a^2 ... n+268=b^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b^2-a^2=168 ... (b-a)(b+a)=168\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factors of 168 ... 1,168 ... 2,84 ... 3,56 ... 4,42 ... 6,28 ... 8,21 ... 12,14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sum of factors is 2b, so it must be even ... 4,42 gives b=23, a=19 ... 23^2-19^2=168\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n+100=19^2 ... n=261 \n" ); document.write( " |