document.write( "Question 1110225: The annual interest on a $19,000 investment exceeds the interest earned on a $12,000 investment by $531. The $19,000 is invested at a 0.4% higher rate of interest than the $12,000. What is the interest rate of each investment? \n" ); document.write( "
Algebra.Com's Answer #725239 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! interest rate on 12000 is x, so the interest is 12000x \n" ); document.write( "for 19000, the interest rate is x+0.004, so the interest is 19000x+76 \n" ); document.write( "12000x+531=19000x+76 \n" ); document.write( "455=7000x \n" ); document.write( "x=455/7000=0.065 \n" ); document.write( "interest is 12000*0.065=$780 \n" ); document.write( "x+0.004 is 0.069 or 6.9% interest rate and 19000*0.069=$1311 \n" ); document.write( "That is $531 higher. \n" ); document.write( "rates are 6.5% and 6.9%\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |