document.write( "Question 99496: A Bank loaned out $12,000, part of it at the rate of 8% per year and the rest at the the rate of 18% per year. If the interest recieved totaled $1000, how much was loaned at 8%? \n" ); document.write( "
Algebra.Com's Answer #72523 by checkley71(8403)\"\" \"About 
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.08X+.18(12000-X)=1000
\n" ); document.write( ".08X+2160-.18X=1000
\n" ); document.write( "-.1X=1000-2160
\n" ); document.write( "-.1X=-1160
\n" ); document.write( "X=-1160/-.1
\n" ); document.write( "X=11600 LOANED @ 8%
\n" ); document.write( "12000-11600=400 LOANED @ 18%
\n" ); document.write( "PROOF
\n" ); document.write( ".08*11600+.18*400=1000
\n" ); document.write( "928+72=1000
\n" ); document.write( "1000=1000
\n" ); document.write( "
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