document.write( "Question 1110215: Given the sequence 3;6;9;.....;60.\r
\n" ); document.write( "\n" ); document.write( "a)Determine the number of terms in the sequence\r
\n" ); document.write( "\n" ); document.write( "b)Determine the sum of the terms in the sequence
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Algebra.Com's Answer #725225 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "a) The numbers are the first 20 multiples of 3; so the number of terms in the sequence is 20.

\n" ); document.write( "More formally...
\n" ); document.write( "\"60-3+=+57\" difference between first and last terms
\n" ); document.write( "\"57%2F3+=+19\" divide by common difference to find the number of terms AFTER THE FIRST TERM
\n" ); document.write( "\"19%2B1+=+20\" you need to count the first term also

\n" ); document.write( "b) Since this is an arithmetic sequence (common difference between successive terms), the average of all the numbers is the average of the first and last.

\n" ); document.write( "Since in ANY set of numbers the sum is equal to the average multiplied by the number of numbers, the sum of the terms in this sequence is

\n" ); document.write( "\"%28%283%2B60%29%2F2%29%2A20+=+63%2A10+=+630\"
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