document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110205>Question 1110205</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A person<BR>\n" );
document.write( "invests a total of R200 000 in money-market accounts at three different banks: Bank A pays 6% interest<BR>\n" );
document.write( "per year on a low risk investment, Bank B pays 6,5% per year on a medium risk investment and Bank<BR>\n" );
document.write( "C pays 8% per year on a high risk investment. Suppose the person invests two times the amount of<BR>\n" );
document.write( "Bank A at Bank B, and the total interest earned after one year is R14 000. Compose three independent<BR>\n" );
document.write( "equations and use reduction of a 3×3 matrix to determine how much was invested at each bank. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725223 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=amount at A<BR>\n" );
document.write( "2x=amount at B<BR>\n" );
document.write( "200,000-3x=amount at C, everything left after A and B.<BR>\n" );
document.write( ".06x+.065(2x)+.08(200000-3x)=14000<BR>\n" );
document.write( ".19x-.24x+16000=14000<BR>\n" );
document.write( "-.05x=-2000<BR>\n" );
document.write( "x=40000@ 6%=2400 at A<BR>\n" );
document.write( "2x=80000@6.5%=5200 at B<BR>\n" );
document.write( "200000-3x=80000@8%=6400 at C<BR>\n" );
document.write( "adds to 14,000 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );