document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1110199>Question 1110199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of one edge of the cube is 6 cm.<BR>\n" );
document.write( "What is the length of the diagonal EG?<BR>\n" );
document.write( "What is the length of the diagonal Ag?<BR>\n" );
document.write( "Round your answers to 1 decimal place. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #725201 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=725201\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your cube will have two kinds of diagonals.  You can use Pythagorean Theorem formula for both of these kinds.\r<BR>\n" );
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document.write( "Opposite corners of a surface side:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%286%5E2%2B6%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%286%5E2%2B6%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Opposite corners of the CUBE:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%286%5E2%2B6%5E2%2B6%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%286%5E2%2B6%5E2%2B6%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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