document.write( "Question 1110187: Time taken by a boat in covering a distance upstream is 1.5times to that of covering the same distance downstream.What will be the ratio between speed of the boat in still water and that of stream \n" ); document.write( "

Algebra.Com's Answer #725183 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+t+\"$ = time in hrs to travel downstream
\n" ); document.write( " $\"+1.5t+\"$ = time in hrs to travel upstream
\n" ); document.write( "Let $\"+d+\"$ = one way distance
\n" ); document.write( "Let $\"+s+\"$ = the speed of the boat in still water
\n" ); document.write( "Let $\"+c+\"$ = the speed of the current
\n" ); document.write( "------------------------------------------
\n" ); document.write( "Equation for going upstream:
\n" ); document.write( "(1) $\"+d+=+%28+s+-+c+%29%2A1.5t+\"$
\n" ); document.write( "Equation for going downstream:
\n" ); document.write( "(2) $\"+d+=+%28+s+%2B+c+%29%2At+\"$
\n" ); document.write( "--------------------------------
\n" ); document.write( " $\"+%28+s+-+c+%29%2A1.5t+=+%28+s+%2B+c+%29%2At+\"$
\n" ); document.write( " $\"+1.5%2A%28+s+-+c+%29+=+s+%2B+c+\"$
\n" ); document.write( " $\"+1.5s+-+1.5c+=+s+%2B+c+\"$
\n" ); document.write( " $\"+.5s+=+2.5c+\"$
\n" ); document.write( " $\"+s%2Fc+=+2.5%2F.5+\"$
\n" ); document.write( " $\"+s%2Fc+=+5%2F1+\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );