document.write( "Question 1110155: Katherine travels 350 miles in the same amount of time it takes Christine to travel 400 miles.
\n" ); document.write( "Christine’s average speed is 4 mph greater than Katherine’s. Find Katherine’s speed.
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Algebra.Com's Answer #725140 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
Let k be Katherine's speed, and k+4 be Christine's speed. Then:
\n" ); document.write( "350/k=400/k+4
\n" ); document.write( "350k+1400=400k
\n" ); document.write( "50k=1400
\n" ); document.write( "k=28 mph
\n" ); document.write( "☺☺☺☺
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