document.write( "Question 1110148: The length of a rectangle is 2 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #725135 by jorel1380(3719) $\"\"$ $\"About$

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Let w be the width of the triangle. Then the length of the triangle is w+2. So:
\n" ); document.write( "w²+(w+2)²=4²=16
\n" ); document.write( "w²+w²+4w+4=16
\n" ); document.write( "2w²+4w-12=0
\n" ); document.write( "w²+2w-6=0
\n" ); document.write( "(w+1)²=7
\n" ); document.write( "w+1=√7
\n" ); document.write( "w=√7-1
\n" ); document.write( "w+2=√7+1
\n" ); document.write( "The dimensions are √7-1 by √7+1
\n" ); document.write( "☺☺☺☺ \n" ); document.write( "

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