document.write( "Question 1110062: A family includes 3 kids. Determine the probability that:
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document.write( "a. 3 are = 2 boys and one girl
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document.write( "b. there are at least one boy
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document.write( "c. there are children of both sex
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document.write( "d. there is at most one girl \n" );
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Algebra.Com's Answer #725131 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Look at all of the possibilities there are 8 \n" ); document.write( "BBB \n" ); document.write( "BBG \n" ); document.write( "BGB \n" ); document.write( "BGG \n" ); document.write( "GBB \n" ); document.write( "GBG \n" ); document.write( "GGB \n" ); document.write( "GGG \n" ); document.write( "So then, \n" ); document.write( "a) 2B and 1G: BBG, BGB, GBB - 3 outcomes. \n" ); document.write( " \n" ); document.write( "b) Let's do it backwards. No boys - GGG - 1 outcome. \n" ); document.write( "The complement is 7. \n" ); document.write( " \n" ); document.write( "c) Again, use the complement, BBB and GGG - 2 outcomes so, \n" ); document.write( " \n" ); document.write( "d) So no girls or 1 girl, BBB, BBG, BGB, GBB, 4 outcomes, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |