document.write( "Question 1110062: A family includes 3 kids. Determine the probability that:
\n" ); document.write( "a. 3 are = 2 boys and one girl
\n" ); document.write( "b. there are at least one boy
\n" ); document.write( "c. there are children of both sex
\n" ); document.write( "d. there is at most one girl
\n" ); document.write( "

Algebra.Com's Answer #725131 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Look at all of the possibilities there are 8 \"%282%5E3%29\" of them.
\n" ); document.write( "BBB
\n" ); document.write( "BBG
\n" ); document.write( "BGB
\n" ); document.write( "BGG
\n" ); document.write( "GBB
\n" ); document.write( "GBG
\n" ); document.write( "GGB
\n" ); document.write( "GGG
\n" ); document.write( "So then,
\n" ); document.write( "a) 2B and 1G: BBG, BGB, GBB - 3 outcomes.
\n" ); document.write( "\"P=3%2F8\"
\n" ); document.write( "b) Let's do it backwards. No boys - GGG - 1 outcome.
\n" ); document.write( "The complement is 7.
\n" ); document.write( "\"P=7%2F8\"
\n" ); document.write( "c) Again, use the complement, BBB and GGG - 2 outcomes so,
\n" ); document.write( "\"P=6%2F8=3%2F4\"
\n" ); document.write( "d) So no girls or 1 girl, BBB, BBG, BGB, GBB, 4 outcomes,
\n" ); document.write( "\"P=4%2F8=1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );