document.write( "Question 1110118: find a:b:c, given 3a+b=2c and 3b=2c+a. \n" ); document.write( "
Algebra.Com's Answer #725112 by Edwin McCravy(20055)\"\" \"About 
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document.write( "Use the first equation to substitute 3a+b for 2c\r\n" );
document.write( "in the second equation:\r\n" );
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document.write( "3b = 2c+a \r\n" );
document.write( "3b = 3a+b+a\r\n" );
document.write( "3b = 4a+b\r\n" );
document.write( "2b = 4a\r\n" );
document.write( " b = 2a\r\n" );
document.write( "Divide both sides by 2b, to get a/b on the right\r\n" );
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document.write( "\"%28b%29%2F%282b%29+=+%282a%29%2F%282b%29\"\r\n" );
document.write( "\"1%2F2=a%2Fb\"\r\n" );
document.write( "1:2 = a:b\r\n" );
document.write( "a:b = 1:2\r\n" );
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document.write( "Substitute 2a for b in\r\n" );
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document.write( "3a+b  = 2c\r\n" );
document.write( "3a+2a = 2c\r\n" );
document.write( "   5a = 2c\r\n" );
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document.write( "Divide both sides by 5c to get a/c on the left:\r\n" );
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document.write( "\"%285a%29%2F%285c%29+=+%282c%29%2F%285c%29\"\r\n" );
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document.write( "\"a%2Fc=2%2F5\"\r\n" );
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document.write( "a:c = 2:5\r\n" );
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document.write( "So now we have:\r\n" );
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document.write( "a:b = 1:2\r\n" );
document.write( "a:c = 2:5\r\n" );
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document.write( "Since 'a' corresponds to 1 in the first equation and\r\n" );
document.write( "to 2 in the second equation, get them so that a corresponds\r\n" );
document.write( "to the same number in both by multiplying both parts of the \r\n" );
document.write( "first ratio 1:2 by 2, getting 2:4\r\n" );
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document.write( "a:b = 2:4\r\n" );
document.write( "a:c = 2:5\r\n" );
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document.write( "Now that a corresponds to the same number, 2, in both,\r\n" );
document.write( "we can conclude:\r\n" );
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document.write( "a:b:c = 2:4:5\r\n" );
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document.write( "Edwin
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