document.write( "Question 1110106: AB and CD are two parallel chords of a circle such that AB = 24 cm and CD= 10 cm. If the radius of the circle is 13 cm , find the distance between the chords.
\n" );
document.write( "My solution :-
\n" );
document.write( "Construction draw a circle with radius 13 cm . Mark two parallel chords AB and CD. Join OB it will make a right angle triangle, so by using Pythagoras theorem
\n" );
document.write( "In triangle ONB
\n" );
document.write( "OB^2= ON^2 + NB^2
\n" );
document.write( "13^2=ON^2 + 12^2
\n" );
document.write( "169 - 144 = ON^2
\n" );
document.write( "25 sq root = ON
\n" );
document.write( "5 = ON
\n" );
document.write( "Now in the same way join OD
\n" );
document.write( "In triangle OMD
\n" );
document.write( "OD^2 = OM^2 + MD^2
\n" );
document.write( "13^2 = OM^2 + 5^2
\n" );
document.write( "169-25= OM^2
\n" );
document.write( "144 sq root = OM^2
\n" );
document.write( "12 = OM
\n" );
document.write( "Distance between the chords = 12 + 5
\n" );
document.write( "17 cm
\n" );
document.write( "Experts please check whether my answer is wrong or correct
\n" );
document.write( "And check the solution also. I want to know the exact answer\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #725101 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Your solution is fine; but it is only one of two possible answers, as suggested in the response by the other tutor. \n" ); document.write( "Radii to the endpoints of the chords, and a diameter perpendicular to the two chords, create right triangles with hypotenuse 13 and legs either 5 or 12 (because the diameter bisects each chord). Then we know the chord of length 24 is 5 from the center of the circle and the chord of length 10 is 12 from the center. \n" ); document.write( "But your answer assumes the chords are on opposite sides of the center of the circle, making the distance between them 12+5=17. The two chords could be on the same side of the center, making the distance between them 12-5=7. \n" ); document.write( " |