document.write( "Question 1110100: The one-to-one function f is defined below.
\n" ); document.write( "=f(x)=x/5x-4
\n" ); document.write( "Find f^-1, where f^-1 is the inverse of f
\n" ); document.write( ".
\n" ); document.write( "Also state the domain and range of f^-1 in interval notation.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #725099 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The domain of f(x) is all values except 4/5.

\n" ); document.write( "That means the range of f^-1(x) is all values except 4/5.

\n" ); document.write( "To find f^-1(x), switch x and y in the given function and solve for the new y.

\n" ); document.write( "\"x+=+y%2F%285y-4%29\"
\n" ); document.write( "\"x%285y-4%29+=+y\"
\n" ); document.write( "\"5xy-4x+=+y\"
\n" ); document.write( "\"5xy-y+=+4x\"
\n" ); document.write( "\"%285x-1%29y+=+4x\"
\n" ); document.write( "\"y+=+4x%2F%285x-1%29\"

\n" ); document.write( "\"f%5E-1%28x%29+=+%284x%29%2F%285x-1%29\"

\n" ); document.write( "The domain of f^-1(x) is all values except 1/5.

\n" ); document.write( "Graphing the function and the inverse confirm these results.

\n" ); document.write( "The graph of f(x) (red) has a vertical asymptote at x=4/5 and a horizontal asymptote at y=1/5 (green).

\n" ); document.write( "\"graph%28400%2C400%2C-2%2C2%2C-2%2C2%2Cx%2F%285x-4%29%2C1%2F5%29\"

\n" ); document.write( "The graph of f^-1(x) (red) has a vertical asymptote at x=1/5 and a horizontal asymptote at y = 4/5 (green).

\n" ); document.write( "\"graph%28400%2C400%2C-2%2C2%2C-2%2C2%2C%284x%29%2F%285x-1%29%2C4%2F5%29\"

\n" ); document.write( "ANSWER:
\n" ); document.write( "f^-1(x) = 4x/(5x-1)
\n" ); document.write( "Domain: x not = 1/5
\n" ); document.write( "Range: y not = 4/5
\n" ); document.write( "
\n" );