document.write( "Question 1110015: i start walking at 11am and reach my destination by 1pm rowing against the stream.On coming back if start at 2pm, i reach rhe starting point by 3.What is the ratio of speed of the boat to that of stream \n" ); document.write( "
Algebra.Com's Answer #725023 by stanbon(75887)\"\" \"About 
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i start walking at 11am and reach my destination by 1pm rowing against the stream.On coming back if start at 2pm, i reach rhe starting point by 3.What is the ratio of speed of the boat to that of stream
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\n" ); document.write( "Upstream DATA::
\n" ); document.write( "time = 2 hrs ; distance = x miles ; rate = x/2 mph
\n" ); document.write( "Downstream DATA:
\n" ); document.write( "time = 1 hr ; distance = x miles ; rate = x mph
\n" ); document.write( "----
\n" ); document.write( "Equations:
\n" ); document.write( "b - c = x/2
\n" ); document.write( "b + c = x
\n" ); document.write( "----
\n" ); document.write( "2b = (3/2)x
\n" ); document.write( "Speed of boat = (3/4)x
\n" ); document.write( "----
\n" ); document.write( "2c = (x/2)
\n" ); document.write( "Speed of current = (1/4)x
\n" ); document.write( "---
\n" ); document.write( "Ans:: Ratio of speed of boat to speed of current is 3:1
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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