document.write( "Question 1110002: At 09 00 car A starts its journey and traveling at 70 km/h at 10 30.Car B started from the same place and traveled steadily on the same road. Car B took 3 1/2 h to catch up with car A. \r
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document.write( "At 15 24, car B reached its destination. When did car A reach the same destination? \n" );
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Algebra.Com's Answer #725005 by ikleyn(52777)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "(1) At 09:00 car A started its journey and traveled at 70 km/h.\r \n" ); document.write( "\n" ); document.write( "(2) At 10:30 car B started from the same place and traveled steadily on the same road. Car B took 3 1/2 h to catch up with car A. \r \n" ); document.write( "\n" ); document.write( "(3) At 15:24, car B reached its destination. \r \n" ); document.write( "\n" ); document.write( "(4) When did car A reach the same destination? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Catching up moment was at 10:30 + 3 h 30 min = 14:00.\r\n" ); document.write( "\r\n" ); document.write( "From 9:00 till 14:00 the car A moved 5 hours and covered 5*70 = 350 kilometers. \r\n" ); document.write( "\r\n" ); document.write( "From 10:30 till 14:00 car B moved 3.5 hours and covered the same distance. So, its rate was\r \n" ); document.write( "\n" ); document.write( "Answer. The car A reached the same destination point at 16:00.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |