document.write( "Question 1109955: The length of a rectangle is 3ft less than twice the width and the area of the rectangle is 14ft^2. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #724990 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! Let w be the width of the rectangle, and 2w-3 be the length. Then: \n" ); document.write( "w(2w-3)=14 \n" ); document.write( "2w²-3w-14=0 \n" ); document.write( "(2w-7)(w+2)=0 \n" ); document.write( "w=7/2 or -2 \n" ); document.write( "The width is 3-1/2 ft, the length is 4 ft. \n" ); document.write( "☺☺☺☺ \n" ); document.write( " |