document.write( "Question 1110001: At 09 00 car A starts its journey and traveling at 70 km/h at 10 30 car B started from the same place and traveled steadily on the same road. Car B took 3 1/2 h to catch up with car A. Find the speed of Car B.\r
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Algebra.Com's Answer #724985 by ankor@dixie-net.com(22740)\"\" \"About 
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At 09 00 car A starts its journey and traveling at 70 km/h
\n" ); document.write( " at 10 30 car B started from the same place and traveled steadily on the same road.
\n" ); document.write( " Car B took 3 1/2 h to catch up with car A.
\n" ); document.write( " Find the speed of Car B.
\n" ); document.write( "let b = speed of car b
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\n" ); document.write( "When car B catches up with A, the will have traveled the same distance
\n" ); document.write( "Write a distance equation: dist = speed * time
\n" ); document.write( "Car A traveled 1.5 hrs longer than car B. Car A traveled: 3.5 + 1.5 = 5 hrs
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\n" ); document.write( "B's dist = A's dist
\n" ); document.write( "3.5b = 70(5)
\n" ); document.write( "3.5b = 350
\n" ); document.write( "b = 350/3.5
\n" ); document.write( "b = 100 km/hr \n" ); document.write( "
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