document.write( "Question 1109946: With log 2 = .301 and log 3=.477. How am I suppose to find log .006 with those? \n" ); document.write( "

Algebra.Com's Answer #724926 by ikleyn(52814) $\"\"$ $\"About$

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document.write( "0.006 = .\r\n" );
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document.write( "Therefore,  log(0.006) = log(2) + log(3) - log(1000) = log(2) + log(3) - 3 \r\n" );
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document.write( "                       = substitute the given values for log(2)  and  log(3)  and calculate.\r\n" );
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