document.write( "Question 1109932: The length of a new rectangular playing field is is 6 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 602 yards, what are its dimensions?
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Algebra.Com's Answer #724916 by rothauserc(4718)\"\" \"About 
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let l be length and w be width
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\n" ); document.write( "l = 4w + 6
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\n" ); document.write( "2l + 2w = 602
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\n" ); document.write( "2(4w+6) +2w = 602
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\n" ); document.write( "8w +12 +2w = 602
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\n" ); document.write( "10w = 590
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\n" ); document.write( "w = 59
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\n" ); document.write( "l = 4(59) + 6 = 242
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\n" ); document.write( "length is 242 yards and width is 59 yards
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\n" ); document.write( "2(242) +2(59) = 602
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\n" ); document.write( "484 +118 = 602
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\n" ); document.write( "602 = 602
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