document.write( "Question 1109930: hirty percent of salespersons in ABC Ltd. are male. A random sample of 100
\n" ); document.write( "salespersons is selected.
\n" ); document.write( "(a) Which distribution does this scenario fit and why?
\n" ); document.write( "(b) Define the variable of interest, X.
\n" ); document.write( "(c) What are the possible values of X?
\n" ); document.write( "(d) What is the expected number of males?
\n" ); document.write( "(e) What is the standard deviation of the number of males?
\n" ); document.write( "(f) What is the probability that there are exactly 25 males in the sample?\r
\n" ); document.write( "\n" ); document.write( "(g) What is the probability of getting less than 36 males?
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Algebra.Com's Answer #724907 by Boreal(15235)\"\" \"About 
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This is a 1 sample proportion test
\n" ); document.write( "x is the random variable and the proportion of those chosen who are male
\n" ); document.write( "possible values are [0, 100], integers only.
\n" ); document.write( "E(X)=np=0.3*100=30.
\n" ); document.write( "V(X)=np(1-p)=30*0.7=21
\n" ); document.write( "sd is sqrt (21) or 4.6
\n" ); document.write( "probability of 24 males is 100C25*0.3^25*0.7^75=0.0496
\n" ); document.write( "getting fewer than 36 using normal approximation at 35.5
\n" ); document.write( "(35.5-30)/4.6 is z
\n" ); document.write( "z=+1.20
\n" ); document.write( "probability that z < 1.20 is 0.8849.
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