document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1109792>Question 1109792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ship sails for 20km on a course of S 20 degrees W and then 25km on a course of S 25 degrees W. Calculate:<BR>\n" );
document.write( "a) how far the ship is from its original point<BR>\n" );
document.write( "b) how far west the ship is from its original point<BR>\n" );
document.write( "c) the bearing of the ship now from its original point </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #724901 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=724901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A ship sails for 20 km on q course S 20° W and then 25 km on a course S 25° W. <BR>\n" );
document.write( " -----------<BR>\n" );
document.write( " 2 sides and the included angle --> Cosine Law to find the 3rd side.<BR>\n" );
document.write( " ===============<BR>\n" );
document.write( " Calculate<BR>\n" );
document.write( " a) How far south the ship is from its original point<BR>\n" );
document.write( " Cosine Law<BR>\n" );
document.write( " --------<BR>\n" );
document.write( " and how far west the ship is from its original point<BR>\n" );
document.write( " It's a right triangle after finding the 3rd side. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );