document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1109889>Question 1109889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A newspaper carrier has $6.65 in change. He has 5 more quarters than dimes but 4 times as many nickels as quarters. how many coins of each type does he have </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #724849 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=724849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> dimes=x<BR>\n" );
document.write( "quarters=x+5<BR>\n" );
document.write( "nickels=4(x+5) or 4x+20<BR>\n" );
document.write( ".10x+.25(x+5)+.05(4x+20)=6.65<BR>\n" );
document.write( ".10x+.25x+1.25+.20x+1.00=6.65<BR>\n" );
document.write( ".55x=4.40, collecting terms and moving the constants to the right.<BR>\n" );
document.write( "x=8 dimes (0.80)<BR>\n" );
document.write( "x+5=13 quarters (3.25)<BR>\n" );
document.write( "4(x+5)=52 nickels (2.60)<BR>\n" );
document.write( "They add to $6.65 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );