document.write( "Question 1109861: Consider a loaded die, in 10 independent throws the probability that an even number turns up 5 times is twice the probability that even number turns up 4 times. Prepare the probability distribution of the even numbers and compute the mean and variance. Verify your results as.
\n" );
document.write( "1) μ = E(x) = np 2) Var(x) = σ^2 = npq
\n" );
document.write( "Where p = prob. of even number q = 1-p \n" );
document.write( "
Algebra.Com's Answer #724830 by stanbon(75887) ![]() You can put this solution on YOUR website! Consider a loaded die, in 10 independent thr \n" ); document.write( "ows the probability that an even number turns up 5 times is twice the probability that even number turns up 4 times. Prepare the probability distribution of the even numbers and compute the mean and variance. Verify your results as. \n" ); document.write( "1) mean = E(x) = np \n" ); document.write( "2) Var(x) = sigma^2 = npq \n" ); document.write( "Where p = prob. of even number q = 1-p \n" ); document.write( "------- \n" ); document.write( "P(x = 5) = 10C5p^5q^5 \n" ); document.write( "P(x = 4) = 10C4p^4q^6 \n" ); document.write( "------ \n" ); document.write( "Equation: \n" ); document.write( "10C5p^5q^5 = 2[10C4p^4q^6] \n" ); document.write( "p/q = [2*10C4]/10C5 = 5/3 \n" ); document.write( "---- \n" ); document.write( "p = (5/3)q \n" ); document.write( "p + q = 1 \n" ); document.write( "p + (3/5)p = 1 \n" ); document.write( "8/5 p = 1 \n" ); document.write( "p = 5/8 \n" ); document.write( "1) mean = n*p = 10(5/8) = 50/8 = 6.25 \n" ); document.write( "2) Var = npq = 6.25(3/8) = 2.344 \n" ); document.write( "----------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------\r \n" ); document.write( "\n" ); document.write( "-----\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |